100x-16x^2-154=0

Solution for 100x-16x^2-154=0 equation:

100x-16x^2-154=0

a = -16; b = 100; c = -154;
Δ = b2-4ac
Δ = 1002-4·(-16)·(-154)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-12}{2*-16}=\frac{-112}{-32}
=3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+12}{2*-16}=\frac{-88}{-32}
=2+3/4
$